48\pi = \frac{1}{3}\pi r^2 \times 9
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- Question: The volume of a cone is \(48\pi\) cubic units, and its height is \(9\) units. Find the radius of the base of the cone.
- Solution: The volume \(V\) of a cone is given by:
- Substituting the given values, \(V = 48\pi\) and \(h = 9\), we have:
- Cancel \(\pi\) from both sides and simplify:
- = 3r^2
- Dividing both sides by 3 gives:
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